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Cake day: June 13th, 2023

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  • De_Narm@lemmy.worldto196@lemmy.blahaj.zonePhysics rule
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    22 days ago

    I’m trying to apply the most simple math possible and it seems to add up.

    After one second, their distance is √(5² + 1²) = ~5.1 ft

    After two seconds, their distance is √(10² + 2²) = ~10.2 ft

    After three seconds, it’s √(15² + 3²) = ~15.3 ft

    As speed is the rate of change of distance over time, you can see it’s a constant 5.1 ft/s. You’re free to point out any error, but I don’t think you need anything more than Pythagoras’ theorem.

    The question specifically asks for their seperation speed at 5s to ignore any initial change in their speed as they first need to accelerate, I’d assume.


  • De_Narm@lemmy.worldto196@lemmy.blahaj.zonePhysics rule
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    22 days ago

    It’s been a while, but I think it’s quite trivial.

    After one second, they span a right angled triangle, therefore (using a² + b² = c²) their distance is √(5²+1²) = ~5.1 ft

    They move at constant speed, therefore they seperate at 5.1 ft/s. That means at 5s it’s just 5.1 × 5 = 25.5 ft for the distance and their speed is still the same.