using find to sort all pictures in /pics/ by inverted (i.e., most recently accessed first) access time, and filtering only those with an exposure time between 1/20 and 1/100 seconds

find /pics/ -type f \( -iname '*.jpg' -o -iname '*.jpeg' -o -iname '*.png' \) \
  -exec exiftool -ExposureTime -T {} \; -exec bash -c '
    file="$1"
    exposure="$2"

    # Convert exposure to decimal
    if [[ "$exposure" =~ ^([0-9]+)/([0-9]+)$ ]]; then
        num="${BASH_REMATCH[1]}"
        denom="${BASH_REMATCH[2]}"
        exposure_val=$(echo "$num / $denom" | bc -l)
    else
        exposure_val="$exposure"
    fi

    # Filter by exposure between 1/100 and 1/20 seconds
    if (( $(echo "$exposure_val >= 0.01" | bc -l) )) && (( $(echo "$exposure_val <= 0.05" | bc -l) )); then
        atime=$(stat -c %X "$file")  # Access time (epoch)
        echo "$atime $file"
    fi
  ' bash {} $(exiftool -s3 -ExposureTime {}) | sort -nr

In voidtools everything it would be

pic: path:"C:\pics" sort:da-descending ExposureTime:1/20..1/100

But actually doesn’t work because “ExposureTime” is only available as an sorting order not a filter but you get the gist ;)